Calculating Thermal Beam Deflection for Space Boom Arm Design

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SUMMARY

The discussion focuses on calculating the thermal beam deflection for a boom arm designed for space applications, specifically when the top side of the beam reaches 300 degrees while the bottom remains at zero. The relevant equation for this scenario is derived as y = 0.5*alpha*(L^2)(Tb - Tt)/h, where alpha represents the coefficient of thermal expansion (CTE), L is the cantilever length, h is the cantilever depth, Tb is the temperature of the bottom fiber, and Tt is the temperature of the top fiber. The derivation incorporates bending strain and effective stress, leading to a deflection formula of δ = αΔT L²/2h, applicable under small deflection assumptions.

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  • Understanding of thermal expansion and the coefficient of thermal expansion (CTE)
  • Knowledge of beam mechanics, specifically cantilever beam theory
  • Familiarity with stress and strain concepts in materials science
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dmalwcc89
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Hey I am working with a group on a project where we basically have to design a boom arm for use in space. We've got most of the project figured out but there is a section where we have to determine the beam's deflection if the top side of the beam reached a 300 degree temperature while the bottom side was fixed at zero.

Obviously I've seen the equation delta=(thermal constant*length^2*temp change)/thickness but that is reresentative of when the two beam ENDS are differing temperatures, not the two beam SIDES as in my case.

My question is what equation would I be looking at to determine this information?
 
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I tried a quick derivation (too lengthy to show here), and got a cantilever tip deflection of y = 0.5*alpha*(L^2)(Tb - Tt)/h, where alpha = coefficient of thermal expansion (CTE), L = cantilever length, h = cantilever depth, Tb = temperature of cantilever bottom fiber, and Tt = temperature of cantilever top fiber.
 
I get the same answer as nvn, by assuming a bending strain of \epsilon=\alpha\Delta T/2 on the top and -\alpha\Delta T/2 on the bottom, plus an axial strain of \alpha\Delta T/2 to keep the bottom strain-free. For narrow beams, the amount of bending strain would corresponds to an effective stress of \sigma=E\epsilon=\alpha\Delta TE/2, or an effective bending moment of M=\alpha\Delta TIE/h. This applied moment would cause a deflection of \delta=\alpha\Delta T L^2/2h, assuming small deflections. (This may be the same derivation nvn used.)
 

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