Calculating time for Linear actuator to operate?

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SUMMARY

The discussion focuses on calculating the time required for a linear actuator to extend 1.7mm while experiencing a force of up to 4000 Newtons. The actuator operates at a maximum speed of 11mm/s with no force and decreases linearly to 8mm/s at maximum force. The relevant equations of motion, known as "suvat" equations, are identified as s=((u+v)/2)*t and s=u*t+0.5*a*t^2. The participants confirm that these equations can be rearranged to determine the time needed for the actuator's extension under varying forces.

PREREQUISITES
  • Understanding of linear motion and speed variations
  • Familiarity with the "suvat" equations of motion
  • Basic knowledge of force and Newton's laws
  • Concept of linear actuators and their operational characteristics
NEXT STEPS
  • Study the application of "suvat" equations in varying force scenarios
  • Research linear actuator specifications and performance metrics
  • Explore graphical representations of force vs. speed in linear motion
  • Learn about the impact of load on actuator performance and timing
USEFUL FOR

Engineers, robotics enthusiasts, and anyone involved in the design or analysis of linear actuator systems will benefit from this discussion.

mm391
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I have a linear actuator operating on an object that, when pressure acts against it, produces a force up to 4000 Newtons.

The linear actuator operates with a maximum speed of 11mm/s at no force and a minimum speed at maximum force of 8mm/s. Being a linear actuator the speed decrease linearly from 11mm/s to 8mm/s. Is there a way of calculating the time it will take the linear actuator to fully extend 1.7mm from 0 Newtons to 4000 Newtons?

Is it the basic "suvat" equations:

s=((u+v)/2)*t
s=u*t+0.5*a*t^2

and just rearrange them for the vale you want?
 
mm391 said:
I have a linear actuator operating on an object that, when pressure acts against it, produces a force up to 4000 Newtons.

The linear actuator operates with a maximum speed of 11mm/s at no force and a minimum speed at maximum force of 8mm/s. Being a linear actuator the speed decrease linearly from 11mm/s to 8mm/s. Is there a way of calculating the time it will take the linear actuator to fully extend 1.7mm from 0 Newtons to 4000 Newtons?

Is it the basic "suvat" equations:

s=((u+v)/2)*t
s=u*t+0.5*a*t^2

and just rearrange them for the vale you want?
I think the basic equations might suffice. Could you please explain a bit clearly as to when the force acts on the actuator and when it's speed starts changing? (Maybe with a diagram)
 

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