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i've tried and my de equation is :

f = ma

mg-1/40(mg)-10v = m(dv/dt)

dv/dt = g - )1/40)g - (10/m) v

dv/dt = (39/40)g - (10/m) v

v(t) = (39/40)gv - 5(v^2)/m + c

applying the initial condition (x=0, t=o, v=0) => c=0

thus v(t) = (39/40)gv - 5(v^2)/m

is my de is right? how i get t expression from this equation?