Calculating Time for Side-by-Side Cars: Car Kinematics Homework

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Homework Help Overview

The problem involves two cars: a red car that accelerates from rest to a speed of 34.3 m/s over 8.92 seconds, and a blue car that travels at a constant speed of 21.5 m/s. The question seeks to determine the time elapsed until both cars are side-by-side after the traffic light turns green.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss setting the distances traveled by both cars equal to each other to find the time when they are side-by-side. There are attempts to derive equations based on the cars' speeds and acceleration.

Discussion Status

Some participants have provided calculations and attempted to solve for time, while others have cautioned against giving complete answers, emphasizing the forum's approach of guiding understanding rather than providing solutions. There is an acknowledgment of the need for the original poster to engage further with the problem.

Contextual Notes

There is a mention of the importance of considering the period during which the red car maintains its constant speed after acceleration, which may influence the calculations. Additionally, there are reminders about the forum's guidelines on providing hints rather than full solutions.

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Homework Statement



A red car is sitting at a stop light at rest. When the light turns green two things happen simultaneously; (1) the red car accelerates to a speed of 34.3 m/s in 8.92 seconds and then maintains that 34.3 m/s speed and (2) a blue car passes by the red car at a constant speed of 21.5 m/s.

Red Car: Vo=0 Vf=34.3 m/s a=3.84 (34.3/8.92)
Blue Car: Vo=21.5 m/s Vf=21.5 m/s

How much time (in seconds) will have elapsed from when the light turned green until the two cars are side-by-side?

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Homework Equations



distance = 1/2(Vo + Vf)t
distance = volt + 1/2at^2


The Attempt at a Solution



I thought I would make them equal to each other, 1/2(Vo +Vf)t=volt +1/2at^2 And find out what t equals to find out the time however It has yet to work after many attempts. Vo Any help is appreciated.
 
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Youngstabullz said:
A red car is sitting at a stop light at rest. When the light turns green two things happen simultaneously; (1) the red car accelerates to a speed of 34.3 m/s in 8.92 seconds and then maintains that 34.3 m/s speed and (2) a blue car passes by the red car at a constant speed of 21.5 m/s.

Red Car: Vo=0 Vf=34.3 m/s a=3.84 (34.3/8.92)
Blue Car: Vo=21.5 m/s Vf=21.5 m/s

How much time (in seconds) will have elapsed from when the light turned green until the two cars are side-by-side?

I thought I would make them equal to each other, 1/2(Vo +Vf)t=volt +1/2at^2 And find out what t equals to find out the time however It has yet to work after many attempts.

Hi Youngstabullz! Welcome to PF! :smile:

Show us your calculations, and then we can see where you've gone wrong. :smile:

(you have allowed for the period of constant speed of 34.3, haven't you?)
 
x(blue)=21.5*8.92+21.5*t

x(red)=.5*34.3*8.92+34.3*t

and so t=3.03 then the answer is answer=3.03+8.92=11.95 seconds
 
rado5 said:
x(blue)=21.5*8.92+21.5*t

x(red)=.5*34.3*8.92+34.3*t

and so t=3.03 then the answer is answer=3.03+8.92=11.95 seconds

Hi rado5! :smile:

You must stop giving full answers to other people's questions (you've done it before).

You haven't even given Youngstabullz the chance to reply. :frown:

On this forum, we try just to give helpful hints, so that the OP can work the problem out themselves.

Full answers should only be given when all hints have failed.

Please restrain yourself. :smile:

(And your answer was wrong … again! :rolleyes:)
 
Thankfully, I got the answer before you guys had responded to my question. :D
 
Youngstabullz said:
Thankfully, I got the answer before you guys had responded to my question. :D

That's the idea! :smile:
 

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