A car traveling at a constant speed of 24.0m/s passes a trooper hidden behind a billboard. One second after the speeding car passes the billboard, the trooper sets off in a chase with a constant acceleration of 3.0m/s^2.
A) How long does it take the trooper to overtake the speeding car?
B) How fast is the trooper going at the time?
- Vf = Vi+a(t)
- Δd = Vi(t)+1/2(a)(t)^2
- Vf^2 = Vi^2+2(a)(Δd)
- Average Velocity: Δd/Δt
- Average Acceleration: Vf-Vi/Tf-Ti
Vi: Initial Velocity
The Attempt at a Solution
I tried to draw this out first. I know that the Initial Velocity for the trooper has to be 0m/s since they stay hidden behind a billboard before the car passes. and the Acceleration is 3.00m/s^2. I think that a is asking for the time... and I'm guessing that the second question is asking for Final Velocity...
But is 24.0m/s the final velocity for the Car? Or the Initial? Or both? And do I look for the final velocity of the trooper first?