Calculating Torque, M.o.I, and Angular Acceleration

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Homework Help Overview

The discussion revolves around calculating torque, moment of inertia (M.o.I), and angular acceleration in a physics context. Participants are exploring the relationships between these concepts and how they apply to a scenario involving a constant force acting on a rotating object.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply formulas related to angular motion but expresses uncertainty about the correct approach. Some participants clarify the relationship between angular velocity and revolutions per second, while others reflect on their own calculations and reasoning.

Discussion Status

Participants are actively engaging with the problem, with some providing guidance on the formulas to use. There is acknowledgment of different methods leading to the same answer, and a realization about the nature of the force applied to the system has emerged, indicating a productive direction in the discussion.

Contextual Notes

There is a mention of a misunderstanding regarding the nature of the force applied, which was initially thought to be a single push rather than a continuous force, leading to confusion about the acceleration of the system.

Carnivroar
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Torque = 2m * 50N
M.o.I = (400kg * 2m^2)/2
a = 1/8 rad/s^2 = 0.019894368 revs/s^2

I don't even know which formula to use

But I tried this one

ω= ω0 + αt

0.5rev/s = 0 + 0.019894368rev/s^2 * t

t = 23.132

That's seems like a lot of time... not sure if it's right.
 
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You're nearly there. ω is the angular velocity, you have the revolutions per second. Now, if I remember correctly,

ω=2∏η
where ω is angular velocity
η is revolutions per second
 


Ooops, I mean 25.132, that was a typo. Is that the correct answer?
 


Yes, that is the answer I get, just got there in a different way.
 


TaxOnFear said:
Yes, that is the answer I get, just got there in a different way.

Good then

I figured it out, my mistake was thinking that the 50N push was just one push and then release, so I was confused as to why the merry-go-round would accelerate.

But it's a constant 50 N force, which is why it's accelerating, did not realize that at first.

Thanks
 

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