Calculating Triangle Area: S1, S2 and ABF

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Semo727
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Triangle Area

Hello!
I came across this: On the picture there is triangle ABC with the unknown area S. All we know is, that area of triangle ABF is S1 and area of FGC is S2. And line AB is parallel with line FG. What is the area of triangle ABC? Thanks for your help!

Im sorry for title of this thread: Triangle volume, I wanted to say "area"(a^2).

And now, I will write what I managed to get:
[tex]S=\frac{S_2}{2}+S_1+\sqrt{\frac{S_2^2}{4}+S_1 S_2 }[/tex]
but, I'm not sure if its right and I don't like the way I got it, could you please tell me what was your way?
 
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  • Triangle ABC with F on side AC and G on side BC, where FG is parallel to AB. Segment FB divides the figure into region S1 (triangle ABF) and region S2 (triangle FGC). Tick marks show FG and AB are equal length.
    triangle.jpg
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Last edited:
Semo727 said:
Hello!
I came across this: On the picture there is triangle ABC with the unknown area S. All we know is, that area of triangle ABF is S1 and area of FGC is S2. And line AB is parallel with line FG. What is the area of triangle ABC? Thanks for your help!

Im sorry for title of this thread: Triangle volume, I wanted to say "area"(a^2).

And now, I will write what I managed to get:
[tex]S=\frac{S_2}{2}+S_1+\sqrt{\frac{S_2^2}{4}+S_1 S_2 }[/tex]
but, I'm not sure if its right and I don't like the way I got it, could you please tell me what was your way?

I don't know how you got it, but my answer is the same, so at least you know it's correct. :smile:

-Dan