Water droplet coalescence - prove S < S1 + S2

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The discussion revolves around proving the inequality S < S1 + S2 for two coalescing water droplets with different radii, volumes, and surface areas. Participants emphasize that the problem is primarily mathematical, focusing on the geometric relationships between the droplets rather than surface tension, which is deemed irrelevant to the proof. The conversation includes attempts to manipulate equations for volume and surface area, leading to the conclusion that substituting variables appropriately can help establish the desired inequality. Ultimately, the participants agree that while surface tension is a factor in droplet formation, it does not contribute to solving this specific mathematical problem. The focus remains on algebraic manipulation to demonstrate the inequality.
  • #31
Oh wait. those are for a single variable x, whereas I essentially have an x and a y... Not sure which rule to use here.

0 < (R1 - R2)^2 would give me something close but those 3's I'm not sure what to do with.
 
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  • #32
bioinformaticsgirl said:
Oh wait. those are for a single variable x, whereas I essentially have an x and a y... Not sure which rule to use here.

0 < (R1 - R2)^2 would give me something close but those 3's I'm not sure what to do with.
What's the obvious way to get 3R12+3R22 from R12+R22 ?
 
  • #33
bioinformaticsgirl said:
Using the square of a binomial where (u + v)2 = u2 - 2uv +v2 I would think I can find the sum of terms with this, but I'm not totally sure what to do with those 3's.

I rewrite into standard form:
0 < 3R12 - 2R1R2 + 3R22
Suppose you wrote ##3R_1^2+3R_2^2-2R_1R_2=2R_1^2+2R_2^2+(R_1^2-2R_1R_2+R_2^2)##
Would that help?
 

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