Water droplet coalescence - prove S < S1 + S2

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Homework Help Overview

The discussion revolves around proving the inequality S < S1 + S2 for two coalescing water droplets with different radii, volumes, and surface areas. The original poster presents the problem in the context of geometric properties of spheres and the relationship between volume and surface area.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between the surface areas and volumes of the droplets, with some suggesting the need to incorporate surface tension into the discussion. Others question the relevance of surface tension, asserting that the problem is primarily mathematical.

Discussion Status

The conversation is ongoing, with participants sharing their attempts to manipulate the equations for volume and surface area. Some have provided guidance on substituting variables and simplifying expressions, while others express uncertainty about the assumptions being made.

Contextual Notes

There is a mention of potential confusion regarding the role of surface tension in the problem, with differing opinions on its relevance. The original poster and some participants are working to clarify the mathematical relationships without reaching a consensus on the necessity of surface tension in the proof.

  • #31
Oh wait. those are for a single variable x, whereas I essentially have an x and a y... Not sure which rule to use here.

0 < (R1 - R2)^2 would give me something close but those 3's I'm not sure what to do with.
 
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  • #32
bioinformaticsgirl said:
Oh wait. those are for a single variable x, whereas I essentially have an x and a y... Not sure which rule to use here.

0 < (R1 - R2)^2 would give me something close but those 3's I'm not sure what to do with.
What's the obvious way to get 3R12+3R22 from R12+R22 ?
 
  • #33
bioinformaticsgirl said:
Using the square of a binomial where (u + v)2 = u2 - 2uv +v2 I would think I can find the sum of terms with this, but I'm not totally sure what to do with those 3's.

I rewrite into standard form:
0 < 3R12 - 2R1R2 + 3R22
Suppose you wrote ##3R_1^2+3R_2^2-2R_1R_2=2R_1^2+2R_2^2+(R_1^2-2R_1R_2+R_2^2)##
Would that help?
 

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