Calculating Variance of Y with X1, X2,...,X15

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The variance of the random variable Y, defined as Y = Σ(j*Xj) for j from 1 to 15, where each Xj is an independent random variable taking values +1 and -1 with equal probability, can be calculated using the formula VAR(Y) = E(Y^2) - (E(Y))^2. The expected value E(Y) is 0, and the variance VAR(Y) can be determined by applying the properties of variance for independent random variables, specifically VAR(Y) = Σ(j^2 * VAR(Xj)). Given that VAR(Xj) = 1 for each Xj, the final variance VAR(Y) equals 1/4 * Σ(j^2) from j=1 to 15.

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The random variable X1, X2,...,X15 are independent and take each values ​​ +1,-1 with probability 1/2.

We define Y = sum from j=1 to 15(j*Xj)

whats is the variance VAR(Y)=?

i will find this with VAR(Y)=E(X^2)-(E(X)^2) but how i can find them?
 
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ParisSpart said:
The random variable X1, X2,...,X15 are independent and take each values ​​ +1,-1 with probability 1/2.

We define Y = sum from j=1 to 15(j*Xj)

whats is the variance VAR(Y)=?

i will find this with VAR(Y)=E(X^2)-(E(X)^2) but how i can find them?
Your book probably has some theorems that cover finding the variance of a sum of multiple of random variables, such as the following.

If X and Y are random variables, and a and b are constants, then
1. Var(X + Y) = Var(X) + Var(Y) + 2Covar(X, Y)
2. Var(aX) = a2Var(X)
 

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