Calculating Velocity, Acceleration, and Net Force for a Bungee Jumper

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Homework Help Overview

The discussion revolves around calculating the velocity, acceleration, and net force experienced by a bungee jumper. The scenario involves a man of 80 kg who falls for 5 seconds before the bungee cord begins to stretch, followed by a 3-second period to come to rest. Participants are exploring the implications of gravitational acceleration and the application of kinematic equations.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to apply kinematic equations to determine the jumper's velocity and acceleration before and after the bungee cord stretches. There is a question about the assumption of the jumper's location, specifically whether he is on Earth, which affects the calculations.

Discussion Status

Some participants have provided calculations for the jumper's velocity and acceleration, while others have prompted for the original poster to show their work before receiving further assistance. There is a discussion about the average net force, with differing interpretations of the results based on the time intervals of forces acting on the jumper.

Contextual Notes

Participants are operating under the assumption that the jumper is on Earth, which is critical for applying gravitational acceleration in their calculations. There is also a requirement for showing work as part of the forum's guidelines for receiving help.

cary5
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have a question pleasezzzzzzzzz help :)
a man of 80 kg falls for 5s befor the bungee cords start to stresch. it takes 3s to bring the man to rest.
(a) what is the man's velocity before the bungee cord starts to strech
(b) what is his acc. before and after the cord stars to strech
(c) what is the ave. net force on the man

i don't knoe if the man is on Earth so can't calculat for velocity non of the formulas work
 
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cary5 said:
have a question pleasezzzzzzzzz help :)
a man of 80 kg falls for 5s befor the bungee cords start to stresch. it takes 3s to bring the man to rest.
(a) what is the man's velocity before the bungee cord starts to strech
(b) what is his acc. before and after the cord stars to strech
(c) what is the ave. net force on the man

i don't knoe if the man is on Earth so can't calculat for velocity non of the formulas work

Of course he's on Earth. Where else in the galaxy to people bungee jump?

So show us the kinematic equations of motion for constant acceleration (the ones you are learning to use for gravity-based questions like this), and show us your work on the solutions to the above questions... You must show your work here before we can offer tutorial help (see the Rules link at the top of the page).
 
berkeman said:
Of course he's on Earth. Where else in the galaxy to people bungee jump?

So show us the kinematic equations of motion for constant acceleration (the ones you are learning to use for gravity-based questions like this), and show us your work on the solutions to the above questions... You must show your work here before we can offer tutorial help (see the Rules link at the top of the page).

ok so Vf=Vi+at
=0+(-9.81)(5s)
=-49.1 m/s
acc. before the b cord statrts to strch would be -9.81m/s2
 
cary5 said:
ok so Vf=Vi+at
=0+(-9.81)(5s)
=-49.1 m/s
acc. before the b cord statrts to strch would be -9.81m/s2

Great!
 
berkeman said:
Great!

so the acc after the b cord starts to stesh is (Vf-Vi)/t
Vi is the velocity we just calculated and Vf is 0 =(-49.1-0)/3s
-16.4 m/s2

the Vi and Vf of the whole systm is 0. Fnet=pf-pi/t
0-0/3
is the net force 0N?
 
cary5 said:
so the acc after the b cord starts to stesh is (Vf-Vi)/t
Vi is the velocity we just calculated and Vf is 0 =(-49.1-0)/3s
-16.4 m/s2

the Vi and Vf of the whole systm is 0. Fnet=pf-pi/t
0-0/3
is the net force 0N?

They ask for the average net force, which I think is zero as you say. That's because the higher force (acceleration) acts for a proportionally shorter time.
 
berkeman said:
They ask for the average net force, which I think is zero as you say. That's because the higher force (acceleration) acts for a proportionally shorter time.

ok thak you
 

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