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## Homework Statement

A bungee jumper with a mass of 78kg tied to a 39 m cord jumps off a bridge from a height of 69 m. She falls to 6 .0m above the ground before the chord brings her momentarily to rest. Calculate the impulse exerted on the jumper by the cord as it stretches

## Homework Equations

Ft = mvf - mvi

P = mv

Eg = mgh

Ep = 1/2 x k^2

Ek = 1/2 m v ^2

## The Attempt at a Solution

Impulse = 0 - mvi

To find vi:

Ek1 + Eg1 = Eg2 + Ep2

So here is where I'm stuck. The equation is impossible to solve because there are two unknowns (spring constant and velocity)