Calculating Velocity in Circular Motion

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Homework Help Overview

The discussion revolves around calculating velocity in the context of circular motion and energy conservation. Participants explore the relationships between kinetic and potential energy, as well as the implications of height changes in a given scenario.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants express uncertainty about how to begin solving the problem, referencing various equations and the potential relevance of circular motion. Questions arise regarding the identification of energy forms and the significance of velocity in the context of energy conservation.

Discussion Status

Some participants have offered insights into the types of energy involved, while others are questioning the assumptions related to height and velocity. There is an ongoing exploration of energy changes, but no explicit consensus has been reached regarding the approach to the problem.

Contextual Notes

Participants mention constraints such as time and the need for specific velocity values. The discussion also highlights the potential introduction of π in the context of circular motion, although its relevance remains uncertain.

mccarthyp64
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1. All in the picture



2.v2=u2+2as



3. I have no idea where to start, I went through all the equations but i don't have time or velocity to sub in :(

It also has circular motion which may or may not introduce pi. I didn't think this would be relevant but anyway.
 

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mccarthyp64 said:
1. All in the picture



2.v2=u2+2as



3. I have no idea where to start, I went through all the equations but i don't have time or velocity to sub in :(

It also has circular motion which may or may not introduce pi. I didn't think this would be relevant but anyway.

The question concerns energy and energy conservation. What forms of energy can you identify in the scenario?
 
There is kinetic and potential gravitational energy
so Ek=1/2mv2 but that needs velocity so:
Ep=mgh but that only gives horizontal velocity whereas, I need all velocity.
 
mccarthyp64 said:
There is kinetic and potential gravitational energy
so Ek=1/2mv2 but that needs velocity so:
Ep=mgh but that only gives horizontal velocity whereas, I need all velocity.

Why do you need velocity? What will velocity tell you?

Why do you suppose that the height of the object only reaches 0.14 m after it breaks the pencil rather than returning to its starting height of 0.30 m? What has changed?
 
for q 25 velocity is the answer
and in 26 I need the work done
 
mccarthyp64 said:
for q 25 velocity is the answer
and in 26 I need the work done

Both questions involve changes in energy. Consider the energy changes taking place.
 
Ep=mgh=Ek=1/2mv2
1.176=0.4*9.8*0.3=1.176=0.5(0.4)(v)2
(1.176/0.5)/0.4=v2=5.88
√(5.88)=2.42=ANS!
YAY thanks gneill :)
 

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