Calculating Ventilation Effect Watts in a Room

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SUMMARY

The discussion focuses on calculating the ventilation effect in Watts for a room using the equation \(\dot Q = \dot V \cdot 0.335 \cdot (T_A - T_O)\), where 0.335 represents the specific heat capacity (Cp) of air. The equation requires careful consideration of units, as the left side represents power in Watts (J/s) while the right side involves volume flow rates. To accurately account for the energy needed to heat incoming air, it is essential to convert volume flow rates to mass flow rates, ensuring consistent units throughout the calculation.

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TSN79
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I want to calculate how much effect in Watts a ventilation system brings into a room. Will it be correct to use the following equation for this:

[tex] \dot Q = \dot V \cdot 0,335 \cdot \left( {T_A - T_O } \right)[/tex]

where 0,335 is actually the Cp of air derived from [itex]{{1005} \over {3600}} \cdot 1,2[/itex]
TA is the temperature the air enters the room with, and TO is the outside temp.

If the air enters the room with a lower temp than the room, how can the energy needed to heat up this air to room temp be taken into account?
 
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I would think that should work, however, check your units. On the left you have watts, or J/s, on the right you have (m^3/s)(J/kgK)(K) giving you...well not what your looking for. I'm pretty sure you need to change your volume flow to mass flow.
 

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