Calculating Volume of Helium Balloon at Different Temperatures

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SUMMARY

The discussion focuses on calculating the volume of helium gas in a balloon at different temperatures using the ideal gas law. Specifically, it addresses a scenario where 9.9 g of liquid helium evaporates at 4.20 K into a balloon at 1.00-atm pressure. The key formula utilized is the relationship V1/T1 = V2/T2, which allows for the determination of gas volume at varying temperatures, specifically at 23.0 K and 299 K.

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jagged06
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Question from my homework. I'm not exactly sure what I am doing wrong, and it is bugging me. I hope this post is in the right forum.

Imagine that 9.9 g of liquid helium, initially at 4.20 K, evaporate into an empty balloon that is kept at 1.00-atm pressure. What is the volume of the balloon at the following?
(a) 23.0 K (b) 299 K

After missing the question, help was given, but I can't make sense of it:

Apply the ideal-gas law to find the volume of the gas at 4.2 K, and a fixed amount of gas to find its volume at the given temperatures.
 
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you must have the density at 4.2 the you can calculate the volume at 4.2 . then you can calculate the volume at the other temperatures from the equation
V1/T1=V2/T2=V3/T3=...=Vn/Tn
 

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