Calculating Wavelength and Expressions for Standing Waves | Homework Solution

Click For Summary
SUMMARY

The discussion focuses on calculating the wavelength and expressions for standing waves on a string of length 1.5m with a frequency of 25Hz. The wavelength is determined to be 1m, derived from the relationship L=(3*lambda)/2. The maximum amplitude of the wave is 5cm, leading to the expressions for the waves traveling in opposite directions: y = 0.025cos(157t - 6.28x) for the right direction and y = 0.025cos(157t + 6.28x) for the left direction, where omega is 157 rad/s and k is 6.28 m^-1.

PREREQUISITES
  • Understanding of wave mechanics and standing waves
  • Familiarity with trigonometric functions in wave equations
  • Knowledge of angular frequency (omega) and wave number (k)
  • Basic algebra for solving equations related to wave properties
NEXT STEPS
  • Study the derivation of wave equations in different mediums
  • Learn about the effects of tension and mass density on wave speed
  • Explore the concept of superposition in wave mechanics
  • Investigate the applications of standing waves in musical instruments
USEFUL FOR

Students studying physics, particularly those focusing on wave mechanics, as well as educators and tutors looking for clear examples of standing wave calculations.

ee1215
Messages
27
Reaction score
0

Homework Statement



A standing wave has been created on a string of length 1.5m. The frequency of the wave is 25Hz. The ends of the string are nodal points and there are 3 antinodes.
A)What is the wavelength of the standing wave?
B)If the maximum amplitude of the wave is 5cm, write complete expressions, including values for k and w, for the generated wave traveling to the right and the reflected wave traveling left. Take right as the +xˆ direction. (Hint: Remember the standing wave is the sum of two waves of equal amplitudes traveling in opposite directions.)

Homework Equations



omega=2pi*f
k=(2pi)/f

The Attempt at a Solution



A) L=(3*lambda)/2
so the wavelength = 1m

B) A=2.5cm = .025m
omega=2pi*f = 2pi(25) = 157 rad/s
k=(2pi)/h = 2pi/1 = 6.28m^-1

So in the right direction: y = 0.025cos(157t - 6.28x)
and the wave to the left is y = 0.025cos(157t + 6.28x)

Are these correct?
 
Physics news on Phys.org
It looks all right, good job.

ehild
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
7K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 21 ·
Replies
21
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
8K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
5K
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K