Calculating Wavelength of Surface Waves on a Lake

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SUMMARY

The discussion centers on calculating the wavelength of surface waves on a lake, specifically addressing the confusion surrounding the measurement of 2.5 meters between a trough and an adjacent crest. Participants clarify that if the 2.5 meters represents the horizontal distance from trough to crest, the wavelength is indeed 5 meters, as it is the distance from crest to crest. However, if the 2.5 meters is interpreted as vertical separation, the wavelength cannot be determined from this information alone. The consensus is to treat the 2.5 meters as horizontal distance for accurate wavelength calculation.

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Homework Statement


it's stated that 2.5meters separated a trough and an adjacent crest of surfae wave on a lke.


Homework Equations





The Attempt at a Solution



At first I thought if the trough to th crest is 2.5meters then i would double that to get the wavelength from crest to crest. But then when I drew another wave picture, the 2.5 can be the amplitude? so that would make me taking half of the 2.5meters instead?? I think my problrm is not understanding what that statmnt is trying to say. I'm unsure if I would multiply 2.5m by two or divide by half. thanks
 
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phys1618 said:
At first I thought if the trough to th crest is 2.5meters then i would double that to get the wavelength from crest to crest.
That's how I interpreted the problem statement: The horizontal separation between trough and adjacent crest is 2.5 m. (But I admit that it is ambiguous.)

If 2.5 m is the vertical separation between those two points, then you would not be able to find the wavelength (which is what you are asked to find, right?).
 
yes, when i first read it, i thought i should double the 2.5m., but in the statemnt is it referrring it has a standing wave or regular wave? am i thinking too much into the problem? is it as simple as it sounds? =x
but you know, you are right, if 2.5 is the vertical separation between the two, I don't think i can find the wavelength. so go with the first idea?
thank you for the help.
 
phys1618 said:
so go with the first idea?
Yes.
 
=) thank you for your help!
 

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