Calculating Work and Power: 50-N Force on a 2-kg Object

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SUMMARY

The discussion focuses on calculating work and power for a 2-kg object subjected to a 50-N force. In the first problem, the force acting for 2 seconds results in a power output of 2500W, confirming option D as the correct answer. The second problem requires the application of the SUVAT equations, specifically V² = U² + 2as, to determine the work done when the object has moved 2 meters. This highlights the importance of using appropriate equations of motion based on the problem's parameters.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Familiarity with the concepts of work and power
  • Knowledge of the SUVAT equations of motion
  • Basic algebra for solving equations
NEXT STEPS
  • Study the derivation and application of the SUVAT equations
  • Learn how to calculate work done using the formula W = F × d
  • Explore the relationship between force, mass, and acceleration in dynamics
  • Investigate real-world applications of work and power in physics
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of mechanics, particularly in calculating work and power in dynamic systems.

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Homework Statement



65. A 50-N force is the only force on a 2-kg object that starts from rest. When the force has been
acting for 2 s the rate at which it is doing work is:
A. 75W
B. 100W
C. 1000W
D. 2500W
E. 5000W
ans: D

66. A 50-N force is the only force a 2-kg crate that starts from rest. At the instant the object has
gone 2m the rate at which the force is doing work is:
A. 2.5W
B. 25W
C. 75W
D. 100W
E. 500W

Q1 solved but i have no idea how to do the second one!
 
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Look up the standard equations of motion (SUVAT). Some are more useful for problems involving time (eg Q1) and others for displacement (Q2).

Perhaps this one...

V^2 = U^2 + 2as

where s = displacement
 

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