Calculating Work in Physics: Forces and Friction Explained

[Heat]

Homework Statement

Someone pushes a book a distance 1.47 m along a horizontal tabletop with a horizontal force of 2.41 N, the opposing force of friction is 0.620 N.

How much work does force 2.41 N do on the book?
What is the work done on the book by the friction force?
What is the total work done on the book?

Homework Equations

W = Fscos$$\phi$$
W = F * S

The Attempt at a Solution

W
W = 2.63

Edit:
Nvm, I got them all/ :D Just realized it.

 

[member 553083]

Work done by 2.41 N force = 2.41N * 1.47m = 3.54 JoulesWork done by friction force = 0.62N * 1.47m = 0.9084 JoulesTotal work done on the book = 3.54 + 0.9084 = 4.4484 Joules