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Homework Statement
We did an experiment at school. We heated Na_2SO_4*10H_2O so that the water evaportated. We started with 2 gram of the substance, and ended up with 1.8 grams. Unfortunately, not all the water did evaporate because of the equipment we used at school. So the question is, a) how many moles of water evaporated and b) what would the new formula be?
Homework Equations
mol = m(g) / M_m
The Attempt at a Solution
a) Moles of water evaporated:
Know that 0.2 grams of water evaporated.
0.2/18 = 0.011 mol H2O evaporated.
That would be about 2 moles for each mol Na2SO4.
b) 2grams Na_2SO_4*10H_2O \rightarrow Na_2SO_4*xH_2O
M_m of Na_2SO_4*10H_2O is 322g/mol
\frac{2g}{322g/mol} gives 0.0062 mol
M_m of Na_2SO_4 = 142 g/mol
\frac{1.8g}{0.0062 mol}=290.32 g/mol
290.32g/mol - 142g/mol = 148g/mol
M_m of H_2O=18
\frac{142 g/mol}{18g/mol} = 8
So the new formula would be:
Na_2SO_4*8H_2O
Is this right?