Calculation of water of crystallization

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SUMMARY

The forum discussion centers on the calculation of water of crystallization for sodium sulfate decahydrate (Na2SO4·10H2O). The user conducted an experiment where 0.2 grams of water evaporated from an initial 2 grams of the compound, leading to the conclusion that the new formula is Na2SO4·8H2O. The calculations involved determining moles using molar mass values of Na2SO4·10H2O (322 g/mol) and Na2SO4 (142 g/mol). The discussion highlights the importance of accuracy in measurements and the influence of environmental factors on the results.

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Homework Statement


We did an experiment at school. We heated Na_2SO_4*10H_2O so that the water evaportated. We started with 2 gram of the substance, and ended up with 1.8 grams. Unfortunately, not all the water did evaporate because of the equipment we used at school. So the question is, a) how many moles of water evaporated and b) what would the new formula be?

Homework Equations



mol = m(g) / M_m

The Attempt at a Solution



a) Moles of water evaporated:
Know that 0.2 grams of water evaporated.
0.2/18 = 0.011 mol H2O evaporated.
That would be about 2 moles for each mol Na2SO4.

b) 2grams Na_2SO_4*10H_2O \rightarrow Na_2SO_4*xH_2O

M_m of Na_2SO_4*10H_2O is 322g/mol

\frac{2g}{322g/mol} gives 0.0062 mol

M_m of Na_2SO_4 = 142 g/mol

\frac{1.8g}{0.0062 mol}=290.32 g/mol

290.32g/mol - 142g/mol = 148g/mol

M_m of H_2O=18

\frac{142 g/mol}{18g/mol} = 8

So the new formula would be:

Na_2SO_4*8H_2O

Is this right?
 
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No one? This should not be hard..
 
Calculations are almost OK, there is one weak point - you can't be sure you started with decahydrate, as amount of water may depend on many factors (including sample history - was it kept in open/closed bottle, what was humidity at the time and so on). But you can't check it, so your assumption is not bad.

The only thing I don't like is that you ignore accuracy - that is, some numbers are presented with guard digits, while other are presented already rounded down in a rather unpredictable way.

--
 
Borek said:
Calculations are almost OK, there is one weak point - you can't be sure you started with decahydrate, as amount of water may depend on many factors (including sample history - was it kept in open/closed bottle, what was humidity at the time and so on). But you can't check it, so your assumption is not bad.

The only thing I don't like is that you ignore accuracy - that is, some numbers are presented with guard digits, while other are presented already rounded down in a rather unpredictable way.

--
www.titrations.info, www.chemistry-quizzes.info, www.ph-meter.info

Thank you for replying!

What I wrote was just quick. I will be more accurate next time. But again, thanks!
 

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