Consider the curve f(x) = 1/x Consider two points on f(x): Pa and Qa, where the x-coordinate of Pa is a, and the x-coordinate of Qa is a+1. Let La be the line connecting Pa and Qa 1.) Find the equation for La 2.) Find a formula that expresses A(a) = the area between f(x) and La 3.) Determine lim(a-->∞) A(a) and lim(a-->0) A(a) 4.) Does A(a) have an extremum for 0 < a? If yes, determine if it's a minimum or maximu (or neither?), and what value of A(a) is at the extremum. Extra: Redo the problem, where the x-coordinate of Qa is a^2 Okay, so I know that the coordinate of Pa is (a, 1/a) and I know that the coordinate of Qa is (a+1, 1/a+1). So, you have the equation for the line y=mx+b. So, the slope would be [(1/a+1)-(1/a)] / [(a+1)-(a)], which would simplify down to m = -(1) / (a^2+a). Correct? How do I go on from here?