Calorimetry Help: Solving a Problem with Ice Phase Change

  • Thread starter Thread starter PhysicsinCalifornia
  • Start date Start date
  • Tags Tags
    Calorimeter
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 3K views
PhysicsinCalifornia
Messages
58
Reaction score
0
I needed to know if anyone can help me solve a problem.

I am supposed to calculate the final temperature after mixing 250 mL of coffee at 80 degrees C with 250 g of ice at 0 degrees C.

The heat of fusion for ice is 6.01 kJ/mol

The ice undergoes a phase change, but I don't know how to apply it. Can anyone help me?
 
Physics news on Phys.org
Well the heat of fusion says it all. It is 6.01 kJ/mol. That means that it takes 6.01 kJ of heat to melt 1 mol of ice--that is changing 1 mol of ice at 0 degrees C to 1 mol of water at 0 degrees C.

Technically you're supposed to show some work before you can get help here, so if you need more help please post to what extent you've worked the problem out so far.
 
Last edited: