This is the statement out of a paper:
Slurry 10 grams of ZnS with 3mL of .2N Cu(CH3COO)2 solution (corresponding to 0.6 atom % Cu) and 1.7 mL of .2N NH4Cl solution (corresponding to 0.34 atom % Cl)
So my question is how did they calculate the .6 at. % and .34 at. % from the information given
The only equations I could find were for mole fractions and converting from weight percent to atomic percent, but by implementing these techniques I was still not able to reproduce the stated percentages.
The Attempt at a Solution
I attempted to solve this using excel by calculating wt. percent then converting it to atomic percentages and my numbers are smaller than the ones given.
I have also done mole fractions and that doesn't seem to be the right way either
My at. % of Cu was only .145 and for Cl it was .165
I accounted for all species present
I will appreciate any guidance for I have been stuck on this for days