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chawki
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Homework Statement
A radio (power = 150 W) and a water heater (resistance = 40 Q) are connected in
parallel. The current, needed for them is fused at 10 A maximum.
Homework Equations
Does the fuse stand the simultaneous use of the radio and the heater? The voItage is 240 V.
The Attempt at a Solution
r: radio
h: heater
V=Vr=Vh
Itotal=Ir+Ih
Pr=V*Ir
Ir=150/240=0.625 ampere
Vh=R*Ih
Ih = Vh/R = 240/40 = 6 amperes
Itotal = 0.625+6 = 6.625
6.625<10 so the fuse will stand