Can a 10A Fuse Handle a 150W Radio and 240V Water Heater in Parallel?

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SUMMARY

The discussion confirms that a 10A fuse can handle the simultaneous operation of a 150W radio and a 240V water heater with a resistance of 40Ω. The total current drawn by the devices is calculated to be 6.625A, which is below the fuse's maximum rating. The calculations are based on the formulas for power and resistance, ensuring that the fuse will not blow under these conditions.

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  • Understanding of Ohm's Law
  • Basic knowledge of electrical power calculations
  • Familiarity with parallel circuit configurations
  • Ability to interpret electrical specifications and ratings
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Homework Statement


A radio (power = 150 W) and a water heater (resistance = 40 Q) are connected in
parallel. The current, needed for them is fused at 10 A maximum.

Homework Equations


Does the fuse stand the simultaneous use of the radio and the heater? The voItage is 240 V.

The Attempt at a Solution


r: radio
h: heater

V=Vr=Vh
Itotal=Ir+Ih

Pr=V*Ir
Ir=150/240=0.625 ampere

Vh=R*Ih
Ih = Vh/R = 240/40 = 6 amperes

Itotal = 0.625+6 = 6.625
6.625<10 so the fuse will stand
 
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That looks good.
I guess the "40Q" meant "40Ω".
 
Delphi51 said:
That looks good.
I guess the "40Q" meant "40Ω".
yesyes 40Ω , and thank you o:)