Can a Continuous Bijection Have a Discontinuous Inverse?

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find : E[tex]\subseteqR[/tex]

f : E[tex]\rightarrowR[/tex]

1_1 , onto , contonuo

such that

f[tex]^{}-1[/tex] : f(E) [tex]\rightarrowR[/tex]

is not continows

Please help me in finding a solution
 
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Perhaps you meant:

Let [itex]E\subseteq \mathbb{R}[/itex]. Find a function [itex]f : E\rightarrow \mathbb{R}[/itex] that is one-to-one, onto, and continuous such that [itex]f^{-1} : f(E) \rightarrow \mathbb{R}[/itex] is not continuous.

Is this your question?
 
Yes, this is my question:smile:
 
To0ta said:
Yes, this is my question:smile:


Why don't you just type your question? All of the stuff you are doing with special fonts, centering, and font size is distracting.