Can a Non-Invertible Function Become Invertible in Certain Intervals?

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A non-invertible function can become invertible when its domain is restricted to specific intervals. For example, the function f(x) = x^2 is not invertible over all real numbers but becomes invertible when limited to non-negative or non-positive real numbers, yielding inverses of √x and -√x, respectively. The definition of a function includes its domain, meaning that different restrictions create distinct functions. Therefore, it is accurate to state that the function y = x^2 is invertible for x in the interval [0, 4]. The term "inversible" is incorrect; the proper term is "invertible."
ZeroPivot
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can a function that's not inversable be inversible in certain interwalls. is it ok to say its inversable in this specific intervall or can't the function ever be called inversible?
 
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Yes, but technically, it wouldn't be the same function.

For example, f(x)= x^2is not "invertible" because it is neither "one to one" nor "onto". However, if we restrict the domain to the "non-negative real numbers" then its inverse is \sqrt{x}. If we restrict the domain to the "non-positive real numbers" then its inverse is -\sqrt{x}.

However, the domain of a function is as much a part of its definition as the "formula". That is, "f(x)= x^2, for x any real number", "g(x)=x^2, for x any non-negative real number", and h(x)= x^2, for x any non-negative real number" are three different functions. The first does not have an inverse, the last two do.
 
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HallsofIvy said:
Yes, but technically, it wouldn't be the same function.

For example, f(x)= x^2is not "invertible" because it is neither "one to one" nor "onto". However, if we restrict the domain to the "non-negative real numbers" then its inverse is \sqrt{x}. If we restrict the domain to the "non-positive real numbers" then its inverse is -\sqrt{x}.

However, the domain of a function is as much a part of its definition as the "formula". That is, "f(x)= x^2, for x any real number", "g(x)=x^2, for x any non-negative real number", and h(x)= x^2, for x any non-negative real number" are three different functions. The first does not have an inverse, the last two do.

can i say function y=x^2 is inversible for x E [0 ,4] ?
 
Yes, the function
f: [0,4]\to [0,16],\ x\mapsto x^2
is an invertible function because of the domain that has been specified (also it needs to have the right codomain, or it won't be an onto function, but that's more of a technicality that is washed away by restricting the codomain to whatever the range is)
 
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ZeroPivot said:
can i say function y=x^2 is inversible for x E [0 ,4] ?
"Inversible" is not a word - the one you want is invertible.
 
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So why is "reversible" a word and not "revertible"?
 
Mark44 said:
"Inversible" is not a word - the one you want is invertible.

Possibly because the adjectives invertible and reversible come from the verbs to invert and to reverse, respectively.
 

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