1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Can a polynomial model any continuous function?

  1. Oct 17, 2013 #1
  2. jcsd
  3. Oct 17, 2013 #2
    You might look at the Stone-Weierstrss theorem, which says that any continuous function on a closed interval can be approximated by a polynomial function. I'm not sure about the general case offhand, but I strongly suspect that a bump function would provide a counterexample.
  4. Oct 17, 2013 #3


    User Avatar
    Science Advisor

    There is no such thing as "polynomial up to degree ∞". Polynomials must have finite degree. What you are thinking of is Taylor series. And the answer to that question is no: there are smooth functions which are not analytic.

    Edit: I just noticed you said "close fit" and not equal. Disregard what I said above.

    The Stone-Weierstrass theorem states that given a continuous function ##f : [a,b] \rightarrow \mathbb{R}## and an ##\epsilon > 0## there exists a polynomial p(x) with the property
    ##|f(x)-p(x)|<\epsilon## for all ##x\in [a,b]##.

    That is, provided you are willing to specify a fixed error, there always is a polynomial that is close enough. Note how the theorem says nothing about exponents.
    Last edited: Oct 17, 2013
  5. Oct 17, 2013 #4
    Thankyou both for your answers, they have been very helpful. The reason I needed to know this is I am programming a neural network, which will take an input vector in ℝ[itex]^{6}[/itex] (or a higher dimension) and find a function that will map this input to a vector in ℝ[itex]^{3}[/itex].
    I just wanted to make sure that this function can be a polynomial, as I have to pre define the form of this function and its degree. The neural network will use a learning algorithm and hopefully find coefficients that will create a function that correctly maps the input to the output.
    Thanks again, this website never fails to provide help!
  6. Oct 17, 2013 #5
    Also, I might as well ask before this thread closes:
    Do you know a general "rule of thumb" for how many exponents I will need? I've searched all over the web and there are no papers or resources that I can find, apart from this how-to-choose-the-degree...

    each of the elements in the input vector is related to the output vector by the inverses square law. Each element in the input vector represents the reading of a sensor. These sensors will be placed around a radioactive source. The closer the source is to a sensor the larger its value will be. This value is inversely proportional to the square of the distance from the radiation.
    With an array of these sensors there will be a function that maps the input from all of the sensors to a specific location in 3d space. hence a 6+ dimensional input vector and a 3 dimensional output vector.

    There is probably an analytical solution to this problem that I could calculate, however a machine learning approach will be better as the readings on the sensors won't actually be exactly proportional, and a machine learning approach allows for other insights into the source.

    So my question, for this problem, what is an approximate number of exponents I might need? I know this is a very specific question and its a bit off topic for this forum, but I really have no clue where to start. Do these things usually have a range of 4 to 10 exponents? 10 to 100? I'm going to use trial and error to find the best function but I just don't know the range these things usually are in.
  7. Oct 17, 2013 #6


    User Avatar
    Staff Emeritus
    Science Advisor
    Gold Member

    Use the lowest degree possible. Note that if you have n points a n-1 deg polynomial can be cooked up to hit every point EXACTLY... however what happens between the points will not be what you want.

    Also be aware that you cannot extrapolate polynomial fits, you must stay within the defined range. Outside of fit range anything can happen. Most likely it will not be what you want.
  8. Oct 17, 2013 #7


    User Avatar
    Science Advisor

    One of the requirements of Stone-Weierstrauss is that the domain is compact, which ##\mathbb{R}^6## fails.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook