Zafa Pi
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At each edge of a tetrahedron the 2 common faces form a dihedral angle. Can each of these 6 angles be rational multiples of pi?
The discussion centers on the feasibility of a tetrahedron having all six dihedral angles as rational multiples of pi. It is established that for a regular tetrahedron, the dihedral angle is θ° = arccos⅓, which is irrational. The conversation emphasizes the need for equations that relate the six dihedral angles to the five degrees of freedom in tetrahedron geometry. Participants suggest that developing these equations requires a solid understanding of high school level algebra, trigonometry, and solid geometry.
PREREQUISITESStudents and educators in mathematics, particularly those interested in geometry, polyhedra, and the relationships between angles and shapes.
For the regular tetrahedron the dihedral angle is θ° = arccos⅓, which is irrational.Buzz Bloom said:Hi Zafa:
I would assume that it would be useful to see the equations relating the six dihedral angles to the five degrees of freedom in establishing the geometry of a tetrahedron. Have you tried to develop these equations?
Regards,
Buzz
Hi Zafa:Zafa Pi said:Equations good, give me some.
LOLBuzz Bloom said:Hi Zafa:
Developing these equations is not trivial. I estimate it would take me quite a few hours to do this, and I am not sufficiently interested in the problem to do it. I gather from your comment that at the present time you do not yet have the math skills to do it yourself. I think you will need some high school level algebra, some trigonometry, and perhaps also some solid geometry. So, sometime in the future you will likely be able to develop the equations part of your problem yourself. From these, you should then be able to also work out the rest of the problem as well.
I wish you good luck, and also the patience to wait if you cannot find someone to teach you the math skills you need.
Regards,
Buzz