Finding a third plane that has a dihedral angle to two other planes.

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Homework Help Overview

The problem involves finding a third plane that forms a specific dihedral angle with two given planes. The original planes are defined by their equations, and the task is to determine a new plane that passes through a specified point and has a dihedral angle of θ/2 with each of the original planes.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the calculation of the dihedral angle and its cosine, with one participant questioning whether the new plane would bisect the angle formed by the two original planes. There is also confusion about how to derive the normal vector for the new plane from the normals of the original planes.

Discussion Status

The discussion is ongoing, with participants exploring the geometric implications of vector addition in relation to the bisecting of angles. Some guidance has been offered regarding the conditions under which the sum of vectors can bisect an angle, but no consensus has been reached on the method to find the normal of the third plane.

Contextual Notes

Participants are grappling with the definitions and relationships between the normals of the planes and the geometric properties of vector addition. There is an emphasis on visualizing the problem through drawings and understanding the conditions necessary for angle bisecting.

user8899
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Homework Statement



The acute angle between two planes is called the dihedral angle. Plane x−3y+2z=0 and plane 3x−2y−z+3=0 intersect in a line and form a dihedral angle θ . Find a third plane (in point-normal, i.e. component, form) through the point (-6/7,0,3/7) that has dihedral angle θ/2 with each of the original planes. Do the three planes intersect at a point or in a line? Explain all steps carefully.

Homework Equations



cosθ=|n1 (dot product) n2| /|n1||n2|,

The Attempt at a Solution



I found the dihedral angle of the first two planes to be 1/2, but then I'm not sure what to do after that.
 
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user8899 said:

Homework Statement



The acute angle between two planes is called the dihedral angle. Plane x−3y+2z=0 and plane 3x−2y−z+3=0 intersect in a line and form a dihedral angle θ . Find a third plane (in point-normal, i.e. component, form) through the point (-6/7,0,3/7) that has dihedral angle θ/2 with each of the original planes. Do the three planes intersect at a point or in a line? Explain all steps carefully.

Homework Equations



cosθ=|n1 (dot product) n2| /|n1||n2|,

The Attempt at a Solution




I found the dihedral angle of the first two planes to be 1/2, but then I'm not sure what to do after that.

Don't you mean you found the cosine of the dihedral angle to be 1/2? Wouldn't your new plane bisect the dihedral angle? Can you get its normal from the given normals?
 
LCKurtz said:
Don't you mean you found the cosine of the dihedral angle to be 1/2? Wouldn't your new plane bisect the dihedral angle? Can you get its normal from the given normals?

Yes, that is what I meant. Do we add the two normals to get the third normal? I am really confused.
 
user8899 said:
Yes, that is what I meant. Do we add the two normals to get the third normal? I am really confused.

Think about it and draw some pictures. Say you have two vectors with their tails at the same place. Will their sum bisect the angle between them or do you have to have some condition on the vectors to make it happen?
 
LCKurtz said:
Think about it and draw some pictures. Say you have two vectors with their tails at the same place. Will their sum bisect the angle between them or do you have to have some condition on the vectors to make it happen?

No because the vectors have to be tip to tail to add up?
 
user8899 said:
No because the vectors have to be tip to tail to add up?

No they don't. Think about the parallelogram rule for addition of vectors. The sum is the diagonal of the parallelogram. What has to be true about the two original vectors for that sum vector to bisect the angle between them?
 

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