Can All Banach Spaces Be Structured as Unitary Banach Algebras?

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Discussion Overview

The discussion revolves around whether all Banach spaces can be structured as unitary Banach algebras. Participants explore the relationship between Banach spaces and Banach algebras, particularly in the context of spectral properties of linear operators and the existence of multiplication operations that would allow a Banach space to be considered a Banach algebra.

Discussion Character

  • Debate/contested
  • Conceptual clarification
  • Mathematical reasoning

Main Points Raised

  • One participant references Kolmogorov-Fomin's work, noting unproven statements about the spectral radius and spectrum of linear operators in Banach spaces, and questions if all Banach spaces can be structured as unitary Banach algebras.
  • Another participant expresses doubt about the feasibility of structuring Hilbert spaces as algebras.
  • A participant suggests that the space of continuous linear maps on a Banach space forms a Banach algebra, which may be relevant to the original question.
  • It is pointed out that continuous linear operators on a Banach space belong to a Banach algebra, implying the spectrum of such operators is non-empty.
  • One participant proposes a reverse situation where, given a Banach algebra, a corresponding Banach space could be found such that the algebra represents continuous linear maps on that space.
  • Another participant seeks clarification on whether the original question pertains solely to the non-emptiness of the spectrum of linear operators.
  • A participant questions the clarity of the original question and asks for further explanation from the thread starter.
  • One participant wonders if a Banach space can be treated as a unitary algebra by defining a multiplication operation among its vectors.
  • Another participant clarifies that extending a Banach space into an algebra involves adding multiplication, which fundamentally alters its structure.
  • One participant articulates the definition of a Banach algebra and rephrases the original question regarding the existence of a multiplication operation for any given Banach space.
  • A participant admits uncertainty regarding the original question's implications.
  • Another participant expresses confusion over how the clarified question relates to the initial focus on the non-emptiness of the spectrum.
  • A participant reiterates the connection between Banach spaces and Banach algebras, affirming the relevance of continuous linear maps.

Areas of Agreement / Disagreement

Participants express differing views on the feasibility of structuring Banach spaces as unitary Banach algebras, with some questioning the clarity of the original question and others focusing on the implications of spectral properties. No consensus is reached on the main question or its implications.

Contextual Notes

Participants note that the original question may have evolved from a focus on spectral properties, leading to potential misunderstandings about the relationship between Banach spaces and Banach algebras. The discussion reflects various interpretations and assumptions regarding the definitions and properties of these mathematical structures.

DavideGenoa
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I find, in Kolmogorov-Fomin's Элементы теории функций и функционального анализа, at the end of § 5 of chapter IV, several statement on the spectral radius and the non-emptyness of the spectrum of a linear operator ina Banach space, which are left without proof.
Nevertheless, in Tikhomirov's appendix, the same properties are prooven for non-commutative unitary Banach algebras.
I wonder whether all Banach spaces can be provided with the structure of a unitary (not necessarily commutative) Banach algebras...
##\infty## thanks!
 
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I haven't looked at it in detail, but I doubt it. For example, how would you make Hilbert space into an algebra?
 
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I haven't read either of your sources, but the connection between banach spaces and banach algebras seems to be that the space of continuous linear maps on a banach space is a banach algebra. maybe that suffices for your purpose.
 
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If that was not clear, the continuous linear operator T on the Banach space B is itself a member of the Banach algebra of operators, and thus the spectrum of T is non empty.
 
mathwonk said:
I haven't read either of your sources, but the connection between banach spaces and banach algebras seems to be that the space of continuous linear maps on a banach space is a banach algebra. maybe that suffices for your purpose.

Maybe Davide is thinking of a sort of reverse situation. Given a Banach algebra B_A can we always find a Banach space B so that B_A is the algebra of continuous linear maps on B?
 
but if you read his question, :

"I find, in Kolmogorov-Fomin's Элементы теории функций и функционального анализа, at the end of § 5 of chapter IV, several statement on the spectral radius and the non-emptyness of the spectrum of a linear operator ina Banach space, which are left without proof.
Nevertheless, in Tikhomirov's appendix, the same properties are prooven for non-commutative unitary Banach algebras."

it sounds as if he just wants to know the non emptiness of the spectrum of a linear operator. Or am I missing something?
 
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Maybe you're right, mathwonk, but the title says Banach spaces as Banach algebras; can you clarify for us, Davide?
 
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I was wondering whether a Banach space $B$ can be considered a Banach unitary, not necessarily commutative, algebra by defining some canonical multiplication between the vectors of $B$...
 
Well, no, basically you're extending the Banach space which is itself a topological vector space into an algebra by adding a multiplication between the vectors. Banach space + vector multiplication =/= Banach space.

A Banach algebra is thus an enhancement of a Banach space, a richer mathematical notion.
 
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  • #10
I think OP's question is clear. A Banach algebra is ##\langle \mathbb A, ||\cdot||,+, *\rangle##, where ##\langle \mathbb A, ||\cdot||,+\rangle## is a Banach space and ##*: \mathbb A^2\to \mathbb A## is a binary operation satisfying some properties.

The question is: given a Banach space ##\langle \mathbb A, ||\cdot||,+\rangle##, must there always exist some ##*## such that ##\langle \mathbb A, ||\cdot||,+,*\rangle## is a Banach algebra?

A rephrasing of the question is as follows.
Given any Banach algebra, we can get a Banach space by just forgetting about multiplication. If I tell you a Banach space was built this way, does that give you any information about what kind of Banach algebra you're looking at?
 
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  • #11
To answer your question: I have no idea.
 
  • #12
economicsnerd said:
The question is: given a Banach space ##\langle \mathbb A, ||\cdot||,+\rangle##, must there always exist some ##*## such that ##\langle \mathbb A, ||\cdot||,+,*\rangle## is a Banach algebra
Exactly what I meant.
I thank any past, presend and future poster in this thread!
 
  • #13
i am puzzled since the question as clarified has absolutely nothing to do with the non emptiness of the spectrum, which apparently motivated it.
 
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  • #14
@mathwonk: Tikhomirov's appendix, which is about Banach's algebras, proves those statements in the case of Banach spaces with multiplication as unitary non-commutative algebras. Kolmogorov-Fomin's text states them without a proof for Banach spaces (without multiplication). I haven't reached those proofs yet. I will check whether those proofs can be valid for Banach spaces without assuming them to be unitary algebras and I'll let you know. Thank you again!
 
  • #15
mathwonk said:
I haven't read either of your sources, but the connection between banach spaces and banach algebras seems to be that the space of continuous linear maps on a banach space is a banach algebra. maybe that suffices for your purpose.
That is the case. Cfr. p. 519 here, corollary 2 and theorem 2, for those knowing Russian.
Thank you all!
 

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