Is This Second-Order Differential Equation Solvable?

[karthik3k]

Can Anybody Solve This Equation ??

Can anybody solve this eq ??
I have gone thru many books but cudnt find a solution !
PLz help !


Y"+(C1/x)Y'=C2

Where C1, C2 are constants. and
Y"=(d^2y)/dx^2
Y'=dy/dx

 

[himanshu121]

Ok i give u a hint

Put dy/dx=p
=> \frac{d^2y}{dx^2}= \frac{dp}{dx}
so u have
\frac{dp}{dx} + \frac{C_1}{x}p=C_2

Hope u can take it from there

 

[M98Ranger]

Although I cannot provide a specific solution without knowing the values of C1 and C2, this equation can be solved using various mathematical methods such as separation of variables, integrating factors, or power series. It is a second-order differential equation, which means it has two independent variables, and it requires two initial conditions to find a unique solution. It is a challenging equation, and it is not surprising that you were not able to find a solution in your books. I suggest seeking help from a math tutor or an online math forum where experts can guide you through the steps to solve this equation. With the right approach and determination, I believe anybody can solve this equation. Good luck!