Can electrons knock out neutrons?

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SUMMARY

Electrons can theoretically knock out neutrons from a beryllium nucleus, but the probability of this occurring is significantly lower compared to protons or gamma rays due to the lack of net charge on neutrons. The discussion highlights the efficiency of using protons accelerated to 1.7 MeV for neutron production in medical isotope breeding, emphasizing the strong interaction that facilitates this process. The feasibility of using electrons instead of protons raises questions about the required acceleration voltage and the practicality of DC accelerators in commercial applications.

PREREQUISITES
  • Understanding of nuclear physics concepts, particularly neutron interactions
  • Familiarity with particle acceleration techniques, specifically Van de Graaff accelerators
  • Knowledge of energy levels in particle physics, particularly 1.7 MeV thresholds
  • Basic principles of strong interactions in nuclear reactions
NEXT STEPS
  • Research the mechanisms of neutron production using proton acceleration
  • Explore the design and operation of DC accelerators for high-energy applications
  • Investigate the role of strong interactions in nuclear reactions
  • Examine the historical use and advancements of Van de Graaff accelerators in nuclear physics
USEFUL FOR

Physicists, nuclear engineers, and researchers involved in particle physics and medical isotope production will benefit from this discussion.

Murdock
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I know that sufficiently energetic protons and photons (1.7MeV) can knock a neutron out of a beryllium nucleus. Can an electron do the same?
 
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In principle yes, but I would expect that the process is very unlikely as the neutron does not have a (net) charge.
 
What do you think the probability of it occurring would be compared to a a proton or gamma ray doing the same?
 
I don't know, but I guess someone studied it somewhere.
Why do you ask?
 
I was wondering because a commonly used neutron source is to use high voltages to accelerate protons into a target to produce neutrons for breeding medical isotopes. It just seemed to me you should be able to skip the "middle man" and get a higher efficiency out of it.
 
How do you skip something if you replace protons by electrons?
Protons interact with neutrons via the strong interaction, that makes the process much more likely.
 
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Interesting question since photons don't represent a net charge or capture mechanism.
Then again, I don't know if acceleration process is simple and easy when you have to deliver almost 2 MeV.
 
2 MeV is possible with DC acceleration. With protons you can even save 1 MV of high voltage because you can start with negatively charged ions and use the acceleration voltage twice.
 
mfb,
Agreed. Back in the days Van De Grafs were used, millions of volts were routinely developed. Then again, they were pressed into using high pressure containment to mitigate arcing. It does beg the question, what is a reasonable voltage for commercial use?
 
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I don't know if commercial applications use DC accelerators, but I know those do exist in this energy range.
 
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Mike_In_Plano said:
mfb,
Agreed. Back in the days Van De Grafs were used, millions of volts were routinely developed. Then again, they were pressed into using high pressure containment to mitigate arcing. It does beg the question, what is a reasonable voltage for commercial use?

Hmpf! I'm sitting in the control room of a Van de Graaff accelerator that is in use right now. "Back in the days" indeed.
 
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