Can I Solve for A and B in These Equations?

  • Context: High School 
  • Thread starter Thread starter clemon!!
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SUMMARY

The discussion centers on solving the equations 80A = 12000 - AB and 2000A = 2000 - AB to find the values of A and B. Participants confirm that A and B can be determined by manipulating the equations, specifically by subtracting one from the other to eliminate the AB term. Additionally, users inquire about using Excel to automate the calculations, highlighting a need for dynamic solutions in spreadsheet software. The conversation also references online tools like Wolfram Alpha for assistance in solving these equations.

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  • Understanding of algebraic manipulation and solving equations
  • Familiarity with Excel functions and formulas
  • Basic knowledge of online mathematical tools like Wolfram Alpha
  • Experience with variable substitution in equations
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  • Learn how to use Excel to create dynamic models for solving equations
  • Explore algebraic techniques for eliminating variables in equations
  • Research online calculators that handle polynomial equations
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Mathematicians, students, hobbyists in music production, and anyone interested in solving algebraic equations using software tools.

clemon!!
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80A = 12000 - AB
2000A = 2000 - AB

I can find A and B right? If not I can provide more??


Thanks :o !
 
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Yes you can find out A and B !
 
also is there any way to set up excel so that as i change the figures the answer what A and B is automatically changes?

i'm sorry to be so bad at math - it's been like 12 years since i stuided any :o
 
lazyaditya said:
Yes you can find out A and B !

honestly - i am using software that runs out in like 20 hours. this is a music hobby thing - i don't suppose you can give me the answer plus also if excell will do it for me?? i know it'd be simple for everyone here... :) :) !there are online calculators but they don't seem to cope with the A*B component!
 
Hey clemon.

Minus the first equation from the second and collect the terms for the A's and solve for A. Then plug A into one of the equations and solve for B.
 
they don't converge!

what about:

100=A/(100-B)+C
12000=A/(80-B)+C
200=A(5000-B)+C
thanks!
 
thanks - I'm trying to find it with excel atm. not sure if these figures even converge tbh.
 
80A = 12000 - AB
2000A = 2000 - AB

Didn't you consider getting rid of the "AB" term by subtracting one equation from the other? 80A- 2000A= -1920A= 10000. Solve that for A and then solve either of the two equations, using that value of A, for B
 

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