Can imaginary position operators explain real eigenvalues in quantum mechanics?

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SUMMARY

The discussion centers on the application of imaginary position operators, specifically denoted as ix, in quantum mechanics to yield real eigenvalues from non-hermitian operators. The integral expressions < Bx, x > and < Bix, ix > demonstrate that real (but negative) eigenvalues can be obtained when using the imaginary position operator. The participant expresses a lack of literature on this unconventional approach, highlighting its connection to non-hermiticity and the necessity of further exploration into complex operators and eigenvalues in quantum mechanics.

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SeM
Hello, some operators seem to "add up" and give real eigenvalues only if they are applied on the imaginary position, ix, rather than the normal position operator, x, in the integral :

\begin{equation}
\langle Bx, x\rangle
\end{equation}

when replaced by:\begin{equation}
\langle Bix, ix\rangle
\end{equation}

or\begin{equation}
\langle Bix, x\rangle
\end{equation}

So using (2) or even (3) I get real (but negative) eigenvalues, instead of complex eigenvalues. I have not found any literature on such an absurd thing, as the imaginary position, however, being the only answer to these operators, I am wondering if anyone can point to some further literature on complex operators and complex eigenvalues in QM and whether (2) and (3) make any sense at all

Thanks
 
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What's ##B##? Without clear definitions, I cannot make any sense of the expressions above. Where does this idea of complex/imaginary position eigenvalues come from?
 
It's an idea that comes from a calculation that sums up only if I use an imaginary position operator. Apparently, it is so non-heard of that I will leave it as it is. It has to do with non-hermiticity, where B (not hermitian) only gives a real value on that integral if the position is imaginary.

Thanks!
 

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