Can Infinitely Reordered Products Converge to Different Values?

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SUMMARY

The infinite product \(\prod^{\infty}_{n=1}(1-\frac{x^n}{n})\) converges for \(|x|<1\) and relates to elliptic functions. To analyze its convergence, one can apply the series test to the logarithm of the product, transforming it into a power series expansion. The logarithmic form \(\ln(1+z) = \sum_{k=1}^{\infty} (-)^{k+1}z^k\) is crucial for expressing the product as an infinite sum. Caution is advised when reordering terms, as conditional convergence may lead to different values or divergence.

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does the following infinite product converge ? and what to ?

[tex]\prod^{\infty}_{n=1}(1-\frac{x^n}{n})[/tex]

i know it has something to do with elliptic functions ...
 
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I'm not sure except I believe so for |x|<1.
You can apply series test to the infinite sum you get by taking the logarithm of the infinite product.

Consider also the power series expansion:
[tex]\ln \left(1+z\right) = \sum_{k=1}^{\infty} (-)^{k+1}z^k[/tex]
for [itex]|z|<1[/itex].
So you can express the logarithm of your product as an infinite sum of power series.
See if reordering gives you an answer you can use.
 
Be careful with reordering! If a series like that only conditionally converges, then by reordering, the series can converge to a different value (or even diverge).

If it helps, Mathematica is unable to simplify that product, except for trivial values of x.
 

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