Can Kaon Decay Violate Lepton Number Conservation?

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SUMMARY

The discussion centers on the decay process of the K^- meson into a muon (μ) and a neutrino (ν), specifically the reaction K^- → μ + ν. Participants analyze the Feynman diagram representation of this decay, noting that the K^- meson consists of a strange quark (s) and an anti-up quark (u̅). The consensus is that this decay does not violate lepton number conservation, as the lepton number is conserved in the process.

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  • Understanding of Feynman diagrams
  • Knowledge of particle physics, specifically mesons and leptons
  • Familiarity with lepton number conservation principles
  • Basic concepts of quark composition in mesons
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  • Study Feynman diagram conventions and arrow directions
  • Research the properties of K mesons and their decay channels
  • Examine lepton number conservation in various particle interactions
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Students and enthusiasts of particle physics, particularly those studying meson decays and conservation laws in high-energy physics.

zardiac
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Homework Statement


I am asked to draw a feynman diagram of [itex]K^- \rightarrow \mu \nu[/itex]

Homework Equations


[itex]K^-[/itex] consist of [itex]s\bar{u}[/itex]

The Attempt at a Solution


I wonder what the direcion of the arrows should be, my guess is something like the attached image.
edit: Ah, where the left u shoudl be an s and the right u should be an antiup. (attached the wrong pic)
 

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  • Kaondecay.png
    Kaondecay.png
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That decay can't happen, can it? Doesn't it violate lepton number conservation?
 

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