MHB Can Parallelograms Be Constructed in a Convex Hexagon?

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In a convex hexagon ABCDEF, if there is a point M such that the quadrilaterals ABCM and DEFM are parallelograms, it can be demonstrated that there exists another point N such that BCDN and EFAN are also parallelograms. The proof relies on the properties of parallelograms and the geometric relationships within the hexagon. By analyzing the vectors and positions of the points, the existence of point N can be established. This discussion emphasizes the interconnectedness of geometric figures within a convex hexagon. The conclusion reinforces the idea that parallelograms can indeed be constructed in this scenario.
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In a convex hexagon $ABCDEF$ exist a point $M$ such that $ABCM$ and $DEFM$ are parallelograms . Prove that exists a point $N$ such that $BCDN$ and $EFAN$ are also parallelograms.
 

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Proof using vectors:

Let $\vec{a},\vec{b},\vec{c},\vec{d},\vec{e},\vec{f},\vec{m}$ be vectors representing the points $A,B.C,D,E,F,M$. Then $\vec{m} = \vec{c} + (\vec{a} - \vec{b})$. Therefore $$\vec{a} + \vec{c} - \vec{b} = \vec{d} + \vec{f} - \vec{e}$$ and so $$\vec{b} + \vec{d} - \vec{c} = \vec{a} + \vec{e} - \vec{f}.$$ Let $N$ be the point given by the vector $$\vec{n} = \vec{b} + \vec{d} - \vec{c}.$$ Then $N$ has the property that $BCDN$ and $EFAN$ are parallelograms.
 

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