Can some one check my work? Related Rates

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SUMMARY

The discussion focuses on a related rates problem involving a baseball diamond where a player runs from first to second base at a speed of 28 feet per second. The objective is to determine the rate at which the distance from home plate is changing when the player is 30 feet from second base. The correct application of the related rates formula yields a result of 56/√13 feet per second for ds/dt. The solution was confirmed by another participant, emphasizing the importance of correctly applying the Pythagorean theorem in the context of related rates.

PREREQUISITES
  • Understanding of related rates in calculus
  • Familiarity with the Pythagorean theorem
  • Basic knowledge of differentiation
  • Ability to interpret geometric problems involving distances
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  • Study the application of the Pythagorean theorem in related rates problems
  • Practice additional related rates problems from calculus textbooks
  • Learn how to identify when to apply negative signs in related rates scenarios
  • Explore advanced related rates problems involving multiple variables
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Students studying calculus, particularly those focusing on related rates, educators teaching calculus concepts, and anyone seeking to improve their problem-solving skills in geometry and rates of change.

nyr
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The problem is:
For the baseball diamond in exercise 33, suppose the player is running from first to second at a speed of 28 feet per second. Find the rate at which the distance from home plate is changing when the player is 30 feet from second base.
(the picture basically shows a square with 90 ft sides)

__________________________________________________
My solution

Given: dy/dt = 28 ft/sec
Find: ds/dt when x=30

902y2=s2
0 +2y(dy/dt)=2s(ds/dt)
2(60)(28)=2(30√13)(ds/dt)
56/(√13) ft/sec=ds/dt
__________________________

I'm not really sure if its the correct answer because I always seem to mix up negative signs and I wasnt sure if this required one.
If you really need to see the picture its found here:
http://books.google.com/books?id=E5...he player is 30 feet from second base&f=false
Page 151 #34
 
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nyr said:
The problem is:
For the baseball diamond in exercise 33, suppose the player is running from first to second at a speed of 28 feet per second. Find the rate at which the distance from home plate is changing when the player is 30 feet from second base.
(the picture basically shows a square with 90 ft sides)

__________________________________________________
My solution

Given: dy/dt = 28 ft/sec
Find: ds/dt when x=30

902y2=s2
It looks like you left out the + sign on the left side. The equation should be
902 + y2=s2
nyr said:
0 +2y(dy/dt)=2s(ds/dt)
2(60)(28)=2(30√13)(ds/dt)
56/(√13) ft/sec=ds/dt
Looks fine to me.
nyr said:
__________________________

I'm not really sure if its the correct answer because I always seem to mix up negative signs and I wasnt sure if this required one.
If you really need to see the picture its found here:
http://books.google.com/books?id=E5...he player is 30 feet from second base&f=false
Page 151 #34
 

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