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Can someone answer a quick question for me about e field by spheres.

  1. Sep 5, 2011 #1
    So let's say a sphere has radius R and you want to find the e field where R>r and R is equal to or greater than r.

    would the e field for R>r just be 0?
    Wouldn't that also mean it's 0 for R is equal to or greater than r, or does it change because it's EQUAL or greater?
     
  2. jcsd
  3. Sep 5, 2011 #2

    vela

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    The answers depends on how the charge is distributed through the solid sphere.
     
  4. Sep 5, 2011 #3
    sorry, uniformly distributed thorughout the sphere.
     
  5. Sep 5, 2011 #4

    vela

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    OK, in that case, the electric field wouldn't be 0 inside the sphere. You can calculate what it is by applying Gauss's Law.
     
  6. Sep 6, 2011 #5
    i think i got the sphere confused with spherical shell because in the book it keeps switching back and forth. For spherical spheres it would be 0 right for points within the sphere?
     
  7. Sep 6, 2011 #6

    vela

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    Yes, if all the charge is on uniformly distributed on the surface of the sphere, there's no electric field inside.
     
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