Can someone check this for me?

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The prime factorization of 6 in the field Q[sqrt(-1)] is expressed as 6 = (1+sqrt(-1))(1-sqrt(-1)) * 3. The discussion confirms that 2 and 3 are prime numbers, while questioning the primality of 1+sqrt(-1) and 1-sqrt(-1) in this context. Participants seek clarification on whether additional information is needed to complete the problem. The conversation emphasizes understanding the nature of prime elements in the given field. Overall, the factorization appears to be correct, and the inquiry about completeness suggests a desire for validation.
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Find the prime factorization of 6 in Q[sqrt(-1)].

Ans : Since 6 = 2*3
so 6 = (1+sqrt(-1)) (1-sqrt(-1)) *3 Q.E.D.

Do I need to add anything to it? Am I done with this question? Please kindly advise me. Thank you very much.
 
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How do you know those are prime?
 
because 2 and 3 are prime.
 
I mean 1+sqrt(-1), 1-sqrt(-1), and 3 in the field Q(sqrt(-1)).
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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