Can Sound Travel Fast Enough to Warn a Man of a Falling Flower Pot?

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SUMMARY

The discussion centers on calculating the time a flower pot can fall before it is too late for a shouted warning to reach a man standing below. The calculations involve determining the time of fall using the equation for free fall and the speed of sound in air. The correct approach requires accounting for the total distance fallen, which is less than 21.6 meters, and the response time of the man, which is 0.300 seconds. The final resolution involved correcting errors in the coefficients used in the calculations.

PREREQUISITES
  • Understanding of kinematics, specifically free fall equations
  • Knowledge of sound wave properties, including speed and pressure amplitude
  • Familiarity with basic algebra for solving equations
  • Concept of response time in physics scenarios
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  • Study the equations of motion for free fall, particularly the impact of initial height on fall time
  • Learn about sound wave properties, including displacement amplitude calculations
  • Explore the relationship between pressure amplitude and displacement amplitude in sound waves
  • Investigate real-world applications of sound travel time in safety scenarios
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Physics students, educators, and professionals interested in kinematics and acoustics, particularly those analyzing real-world applications of sound and motion.

buttterfly41
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A flower pot is knocked off a balcony 21.6 m above the sidewalk and falls toward an unsuspecting 1.79 m-tall man who is standing below. How close to the sidewalk can the flower pot fall before it is too late for a shouted warning from the balcony to reach the man in time? Assume that the man below requires 0.300 s to respond to the warning.

So i (21.6-1.79)m / 343m/s = .05776s + .3s = .35776s to yell and have the man react
then, 21.6m= 1/2 * 9.8m/s2 *T^2 ... T= 2.0996 - .35776s = 1.74181s for latest time to wait before yelling,

so i thought the answer should be: 1/2 * 9.8m/s2 * 1.7418^2 = 14.86m down, so 5.74m from the ground... but that is not correct :(

any ideas where i went wrong?

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Also, A sound wave in air has a pressure amplitude equal to 3.94 X10^-3 Pa. Calculate the displacement amplitude of the wave at a frequency of 10.5 kHz.

(Note: Use the following values, as needed. The equilibrium density of air is p= 1.20 kg/m3; the speed of sound in air is v = 343 m/s. Pressure variations P are measured relative to atmospheric pressure, 1.013 x10^5 Pa.)



so, i thought i would use the equation deltaPmax= pwvsmax
and then i plugged the numbers in (w=2pif=65973)... 1.013E5 = 1.2*65973*343*smax
smax= .00373m ... but again, wrong... so i don't know where to go from here

any help would be greatly appreciated. Thanks
 
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buttterfly41 said:
A flower pot is knocked off a balcony 21.6 m above the sidewalk and falls toward an unsuspecting 1.79 m-tall man who is standing below. How close to the sidewalk can the flower pot fall before it is too late for a shouted warning from the balcony to reach the man in time? Assume that the man below requires 0.300 s to respond to the warning.

So i (21.6-1.79)m / 343m/s = .05776s + .3s = .35776s to yell and have the man react
then, 21.6m= 1/2 * 9.8m/s2 *T^2 ... T= 2.0996 - .35776s = 1.74181s for latest time to wait before yelling,

so i thought the answer should be: 1/2 * 9.8m/s2 * 1.7418^2 = 14.86m down, so 5.74m from the ground... but that is not correct.
In physics one has to do the analysis first using algebra. Once you have the physics down, plug in numbers but not before. It makes it easier to see and it usually saves a lot of work.

First of all, as you have correctly noted, the time required is the time it takes for the sound to travel from the balcony to the man + the response time of the man. What is the total time of fall before the pot reaches the position of the man's head? So what is the time that the pot can fall before the warning is given? Write out the algebraic expression for that time and plug in the numbers. [Hint: the total distance of fall is not 21.6 metres. I think this is where you went wrong]

Second, relate the time it has been falling to the distance it has fallen. Write the algebraic expression for that distance. Plug in your numbers.

AM
 
Last edited:
thank you very much... i fixed both of my problems with your adivce... because for both of them i put in one wrong number for a coefficient... so again, thank you for you help ;0

Jenni
 

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