FactChecker said:
Good question. But relativity says that speed does not simply add like that
To make this more concrete, suppose that you have a rocket that can reach half the speed of light. On the tip of this rocket you mount another rocket that can reach half the speed of light relative to the first. On the tip of this second rocket you mount a third that can reach half the speed of light relative to the second.
One is tempted to think that this achieves one and a half times light speed. But it does not. Under the rules of special relativity,
velocities add according to the rule:$$u = \frac{v+u'}{1 + (vu'/c^2)}$$Here ##u## is the resulting speed of a second stage as measured in the original rest frame, ##v## is the speed of the first stage in the original rest frame, ##u'## is the speed of the second stage as measured relative to the first stage final rest frame. and ##c## is, of course, the speed of light.
If we plug in the numbers we get:$$u = \frac{0.5c + 0.5c}{1 + (0.5 \times 0.5)} = \frac{1c}{1.25} = 0.80c$$We had expected to get ##c## but we only got ##0.8c##.
The reason that the velocity addition of ##u' = 0.5c## does not get us the full ##0.5c## is because that additional ##0.5c## is measured using a different reference frame than our starting ##v = 0.5c##. Distance is contracted, time is dilated and simultaneity is affected. One cannot expect both the first stage frame and the original rest frame to get the same number for the separation rate ##u'## between the first and second stages.
Velocities and separation rates add in the ordinary way if all are measured against a common rest frame. When velocities and separation rates from different rest frames are combined, it is a little like adding apples and oranges.