bill01
Is it possible to prove this:
x^x + y^y < (x+y)^(x+y) for every x,y >=1 ?
x^x + y^y < (x+y)^(x+y) for every x,y >=1 ?
The inequality x^x + y^y < (x+y)^(x+y) holds true for all x, y ≥ 1. Participants in the discussion suggest using derivatives to analyze the slope changes of both sides of the inequality. The expansion of (x+y)^(x+y) demonstrates that it is greater than x^x and y^y, as all terms in the expansion are positive when x and y are greater than 1. An algebraic proof is preferred over graphical methods for a definitive solution.
PREREQUISITESMathematicians, students studying calculus and algebra, and anyone interested in proving mathematical inequalities.