Can the Laplace Inverse be Applied to Divided Transfer Functions?

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Chacabucogod
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I was wondering whether this can be done:

Let's say you have transfer function that goes like this:

[tex]\frac{Y(s)}{U(s)}= \frac{N(s)}{D(s)}[/tex]

Now let's say I divide my transfer into two:

[tex]\frac{Y(s)}{Z(s)}= N(s)[/tex]

[tex]\frac{Z(s)}{U(s)}= \frac{1}{D(s)}[/tex]

Can I apply the Laplace Inverse to these two equation separately and then substitute the value of z(t) on one?

[tex]D(s)Z(s)=U(s)[/tex]

[tex]N(s)Z(s)=Y(s)[/tex]

Thank you!
 
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Of course you can:

You then have:

Y(s)/U(s) = (N(s)*Z(s) ) / (D(s)*Z(s) ) => (shorten right fraction)

Y(s)/U(s) = N(s)/D(s)

No problem, assuming that Z(s) ≠ 0.