MHB Can the polynomial equation $x^8-x^7+x^2-x+15=0$ have real roots?

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Prove that the polynomial equation $x^8-x^7+x^2-x+15=0$ has no real solution.
 
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We have $x^8-x^7 + x^2 -x + 15 = x^7(x-1) + x(x-1) + 15$

each term is positive for $x > 1$ so LHS is greater than 0 so no solution for $ x > 1$

for x = 1 LHS = 15 so x = 1 is not a solution

Further $x^8-x^7 + x^2 -x + 15 = (15- x) + x^2(1-x^5) + x^8 $

Each term is positive for $x < 1$ so LHS is greater than 0 so no solution for $ x < 1$

Hence no real solution
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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