Can this system of equations be solved in real numbers?

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SUMMARY

The system of equations defined by $a(b+c-a^3)=b(c+a-b^3)=c(a+b-c^3)=1$ can be solved in real numbers by transforming it into three separate equations: $ab + ac - a^4 = 1$, $ab + bc - b^4 = 1$, and $ac + bc - c^4 = 1$. The solutions can be derived through inspection and algebraic manipulation, leading to specific values for variables a, b, and c. The discussion emphasizes the importance of recognizing patterns in polynomial equations for efficient problem-solving.

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anemone
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Solve in real numbers the system below:

$a(b+c-a^3)=b(c+a-b^3)=c(a+b-c^3)=1$
 
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a=1, b=1, c=1
a=-1, b=-1, c=-1
 
Wilmer said:
a=1, b=1, c=1
a=-1, b=-1, c=-1

Would you mind sharing how you found the solution? :D
 
Lazily, by inspection:
ab + ac - a^4 = 1
ab + bc - b^4 = 1
ac + bc - c^4 = 1
 
Wilmer said:
a=1, b=1, c=1
a=-1, b=-1, c=-1

Hi Wilmer,

Your answer (without the working, hehehe...) is correct, but the question remains on how we are going to prove those are the only solutions.(Nod)
 

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