MHB Can this system of equations be solved in real numbers?

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The system of equations given is $a(b+c-a^3)=b(c+a-b^3)=c(a+b-c^3)=1$. A solution approach involves simplifying the equations to $ab + ac - a^4 = 1$, $ab + bc - b^4 = 1$, and $ac + bc - c^4 = 1$. The discussion highlights that the solution was found through inspection rather than extensive calculation. Participants are encouraged to share their methods for finding solutions. The focus remains on solving the equations in real numbers.
anemone
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Solve in real numbers the system below:

$a(b+c-a^3)=b(c+a-b^3)=c(a+b-c^3)=1$
 
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a=1, b=1, c=1
a=-1, b=-1, c=-1
 
Wilmer said:
a=1, b=1, c=1
a=-1, b=-1, c=-1

Would you mind sharing how you found the solution? :D
 
Lazily, by inspection:
ab + ac - a^4 = 1
ab + bc - b^4 = 1
ac + bc - c^4 = 1
 
Wilmer said:
a=1, b=1, c=1
a=-1, b=-1, c=-1

Hi Wilmer,

Your answer (without the working, hehehe...) is correct, but the question remains on how we are going to prove those are the only solutions.(Nod)
 

Thread 'Area of Overlapping Squares'

Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?
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