Can Visible Photons Occur From -60.0 eV Electron Transitions?

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SUMMARY

Electron transitions from an energy level of -60.0 eV cannot produce visible photons, as the energy of the emitted photons must fall within the range of 1.8 eV to 3.1 eV to be visible to the human eye. The relevant equations, En=-(Z²E0)/n² and ΔEn→m=-Z²E0(1/n²-1/m²), indicate that for transitions to yield visible light, the energy difference must be calculated and shown to be less than 1.8 eV. Given that the energy levels involved do not allow for such transitions, the conclusion is definitively 'no'.

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Homework Statement


Photons can be observed by the human eye as long as their energies are between 1.8 eV and 3.1 eV. In a particular atom one of the electron energy levels is at -60.0 eV. Can electron transitions, associated with this energy level produce photons that are visible to the human eye? Explain why your answer is ’yes’ or ’no’.

Homework Equations


I'm not sure about these

En=-(Z2E0)/n2

Em=-(Z2E0)/m2

n>m

The Attempt at a Solution


ΔEn→m=-Z2E0(1/n2-1/m2)

Where E0=13.6eV

I know the answer is 'no' and that we are meant to get to a point where n/m<1 to show that the answer is 'no', but I don't know where to go from here.
 
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The photons are produced when the electrons move over from a higher energy level to a lower energy level.
 

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