High School Can we have a complex number in the exponent?

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It is valid to express a real number raised to a complex exponent, as demonstrated by the equation r^c = e^{c \log(r)}. This approach allows for the computation of complex powers of real numbers using the exponential function. Additionally, raising a complex number to a complex power is also meaningful. An example provided is i^i, which results in a real number, specifically e^{-π/2}. The discussion confirms that both r and c can indeed be complex.
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TL;DR
Is it possible to exponentiate a number that is not e to a complex number?
Does it make sense to write ##r^c##
where ## r\in R/e ## and ##c\in C## ?
 
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Yes. It makes sense. Remember that using only traditional real functions, ##r = e^{\ln{r}}##. So you can get the complex power of any real number by way of complex powers of ##e##. In fact, it makes sense to raise a complex number to a complex power.
 
##r^c = e^{c \log(r)}##
Both r and c can be complex here. As a notable example, ##i^i = e^{i \log{i}} = e^{i (\frac{\pi}{2} i)} = e^{- \frac{\pi}{2}}## which is real.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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