- #1
ArielGenesis
- 238
- 0
4
5
11
34
65
111
175
260
505
540
671
what is the next line
5
11
34
65
111
175
260
505
540
671
what is the next line
Can We Predict the Next Number in This Sequence Using Rahmuss' Formula?
- Context: Undergrad
- Thread starter ArielGenesis
- Start date
Click For Summary
Discussion Overview
The discussion revolves around predicting the next number in a given sequence using a formula attributed to a participant named Rahmuss. The sequence is presented in two variations, and participants explore different methods and reasoning to derive the next number. The scope includes mathematical reasoning and exploratory problem-solving.
Discussion Character
- Exploratory
- Mathematical reasoning
- Debate/contested
Main Points Raised
- Initial sequences are presented, with participants questioning the next number.
- One participant suggests the next number could be 802, but this is later dismissed.
- A revised sequence is provided, with a hint that the solution involves summing groups of numbers.
- Another participant details how each number in the sequence can be expressed as the sum of consecutive integers.
- Different proposed next numbers include 870 and 1381, with participants expressing uncertainty about their reasoning.
- One participant describes a systematic approach using differences between numbers in the sequence to derive potential next values.
- There is a suggestion to form a formula based on Rahmuss' approach, including a difference formula and a mention of a cubic polynomial, though coefficients remain unresolved.
Areas of Agreement / Disagreement
Participants do not reach a consensus on the next number in the sequence, with multiple competing views and methods presented. There is ongoing debate about the validity of different approaches and proposed formulas.
Contextual Notes
Some participants express uncertainty about the correctness of their proposed next numbers and methods. The discussion includes various interpretations of how to approach the problem, with no clear resolution on the formula or next number.
Who May Find This Useful
Readers interested in mathematical sequences, problem-solving strategies, and exploratory reasoning in mathematics may find this discussion relevant.
- #2
ArielGenesis
- 238
- 0
really no one got an idea ?
- #3
neveza
- 1
- 0
Is the next number 802.
- #4
Yegor
- 147
- 2
ArielGenesis, maybe you can give any hint?
- #5
ArielGenesis
- 238
- 0
my fault acually, but it is suppose to be
1
5
15
34
65
111
175
260
369
505
671
not much diffrent isn't it.
no neveza, it's not 802
the hint is that it involve listing a group of number and doing sum.
1
5
15
34
65
111
175
260
369
505
671
not much diffrent isn't it.
no neveza, it's not 802
the hint is that it involve listing a group of number and doing sum.
- #6
Jimmy Snyder
- 1,122
- 21
1 = 1
5 = 2 + 3
15 = 4 + 5 + 6
34 = 7 + 8 + 9 + 10
65 = 11 + 12 + 13 + 14 + 15
111 = 16 + 17 + 18 + 19 + 20 + 21
175 = 22 + 23 + 24 + 24 + 26 + 27 + 28
260 = 29 + 30 + 31 + 32 + 33 + 34 + 35 + 36
369 = 37 + 38 + 39 + 40 + 41 + 42 + 43 + 44 + 45
505 = 46 + 47 + 48 + 49 + 50 + 51 + 52 + 53 + 54 + 55
671 = 56 + 57 + 58 + 59 + 60 + 61 + 62 + 63 + 64 + 65 + 66
870 = 67 + 68 + 69 + 70 + 71 + 72 + 73 + 74 + 75 + 76 + 77 + 78
- #7
Rahmuss
- 222
- 0
4
5
11
34
65
111
175
260
505
540
671
1381
Is that anywhere close? You really don't want to know how my messed up mind found that answer though. It might make you go crazy...
Oopss! You posted another one...
1
5
15
34
65
111
175
260
369
505
671
870
Looks like that should be the answer for this second set of numbers.
5
11
34
65
111
175
260
505
540
671
1381
Is that anywhere close? You really don't want to know how my messed up mind found that answer though. It might make you go crazy...
Oopss! You posted another one...
1
5
15
34
65
111
175
260
369
505
671
870
Looks like that should be the answer for this second set of numbers.
Last edited:
- #8
Rahmuss
- 222
- 0
Wow! We got the answers a different way; but I'm sure that they equate.
I did it this way:
C = 6 9 12 15 18 21 24 27 30 ? [ Difference in #'s from B ]
B = 4 10 19 31 46 64 85 109 136 166 ? [ Difference in #'s from A]
A=1, 5, 15, 34, 65, 111, 175, 260, 369, 505, 671, ?
In C, the ? should, of course, be 33, which makes the ? in B = 199, which makes the ? in A = 870
I did it this way:
C = 6 9 12 15 18 21 24 27 30 ? [ Difference in #'s from B ]
B = 4 10 19 31 46 64 85 109 136 166 ? [ Difference in #'s from A]
A=1, 5, 15, 34, 65, 111, 175, 260, 369, 505, 671, ?
In C, the ? should, of course, be 33, which makes the ? in B = 199, which makes the ? in A = 870
- #9
Jimmy Snyder
- 1,122
- 21
Rahmuss, your approach is systematic and works in a large number of cases of this kind of puzzle.
- #10
ArielGenesis
- 238
- 0
sorry, it is my fault. and i yup, jimmy (as usual) got it right
can we form a formula based on rahmuss asnwer. as i also had not notice it. and how could it happen to be 3 if he is going to make D = 3,3,3,3,3,3,3 [diffrence in #'s from c]
can we form a formula based on rahmuss asnwer. as i also had not notice it. and how could it happen to be 3 if he is going to make D = 3,3,3,3,3,3,3 [diffrence in #'s from c]
- #11
Jimmy Snyder
- 1,122
- 21
One possible formula is this difference formula:ArielGenesis said:
A_n = 3 \times A_{n-1} - 3 \times A_{n-2} + A_{n - 3} + 3;
Another would be a cubic polynomial in n, but I haven't figured out the coefficients yet.
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