Can you factor the following two polynomials?

[DrLiangMath]

Can you factor the following polynomials over integers?

\(\displaystyle x^4 + 4\)

\(\displaystyle x^4 + 3 ~x^2~y^2 + 2 ~y^4 + 4 ~x^2 + 5 ~y^2 + 3\)

If not, you can get help from the following free math tutoring YouTube channel "Math Tutoring by Dr. Liang"

https://www.youtube.com/channel/UCWvb3TYCbleZjfzz8HEDcQQ

 

[topsquark]

Hint: \(\displaystyle x^4 +4 = x^4 + 4x^2 - 4x^2 + 4\)

-Dan

 

[DrLiangMath]

(up)

 

[HallsofIvy]

I don't see how that helps. $x^4+ 4$ obviously cannot be factored over the integer, or even over the real numbers.

 

[topsquark]

I don't see how that helps. $x^4+ 4$ obviously cannot be factored over the integer, or even over the real numbers.

As linear factors, yes. But:
\(\displaystyle x^4 + 4 = x^4 + (4 x^2 - 4 x^2) + 4 = (x^4 + 4 x^2 + 4) - 4 x^2 = (x^2 + 2)^2 - 4 x^2 = (x^2 + 2 + 2 x)(x^2 + 2 - 2 x)\)

-Dan

 

[I like Serena]

Just to mention an alternative approach, $$x^4+4=0$$ has 4 imaginary solutions that form conjugate pairs.
The solutions are $$x=\pm 1\pm i$$

If we then put the conjugate pairs together, we get $$(x-(1+i))(x-(1-i))=x^2-2x+2$$ and $$(x-(-1+i))(x-(-1-i))=x^2+2x+2$$ just like topsquark found.