Can you help me factor the expression x^4 - 15x^2 + 9?

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Discussion Overview

The discussion revolves around factoring the polynomial expression x^4 - 15x^2 + 9. Participants explore different methods for factoring, including u-substitution and the quadratic formula, while also referencing techniques like completing the square and the difference of squares.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant suggests using u-substitution by letting u = x^2 to transform the expression into u^2 - 15u + 9.
  • Another participant proposes a method involving a trick to rewrite the expression as (x^4 - 6x^2 + 9) - 9x^2.
  • A participant questions the application of u-substitution and attempts to factor the expression further, leading to (x^2 - 3)(x^2 + 3) - 9x^2.
  • Another participant observes that x^4 - 6x^2 + 9 can be expressed as (x^2 - 3)^2 and suggests that the expression can be factored as a difference of squares.
  • A participant expresses gratitude for the help received and mentions their ongoing studies in quadratic equations, indicating a desire to share personal experiences related to math.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the best method for factoring the expression, as multiple approaches are discussed without agreement on a single solution.

Contextual Notes

Some participants reference specific techniques and transformations, but there is no resolution on the effectiveness or correctness of each method presented. The discussion remains exploratory with various proposed approaches.

Who May Find This Useful

Students studying polynomial factoring, particularly those interested in quadratic equations and different factoring techniques.

mathdad
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Factor the expression.

x^4 - 15x^2 + 9

Let u = x^2

Let x^4 = (x^2)^2

u^2 - 15u + 9

Must I use the quadratic formula here or completing the square?
 
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No, we want to use a trick kaliprasad showed us recently:

$$x^4-15x^2+9=x^4-6x^2+9-9x^2=\left(x^4-6x^2+9\right)-\left(9x^2\right)$$

Can you continue?
 
Can I apply the u-substitution?

Let u = x^2

(u^2 - 6u + 9) - 9u

(u - 3)(u - 3) - 9u

(x^2 - 3)(x^2 + 3) - 9x^2

Yes? No?
 
Last edited:
RTCNTC said:
Can I apply the u-substitution?

Let u = x^2

(u^2 - 6u + 9) - 9u

(u - 3)(u - 3) - 9u

(x^2 - 3)(x^2 + 3) - 9x^2

Yes? No?

What I intended for you to observe is that:

$$x^4-6x^2+9=\left(x^2-3\right)^2$$

$$9x^2=(3x)^2$$

And so the expression can be written as a difference of squares, and then factored as such. :)
 
I will be able to complete the factoring work here thanks to you. Keep in mind that I am now in the quadratic equations chapter of the David Cohen textbook. Lots of interesting questions in this chapter. I will be posting questions in terms of the discriminant, radical equations, literal equations and perhaps a few word problems.

I definitely know more math today since joining this website. Please, remind me to share with you what happened to me at Bank One in Springfield, MO 2006. The Bank One story is related to math and complete embarrassment. Look for a PM from me. I will text 5 general questions today or tomorrow.
 

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